|
Question 1038621: Ashley, Brian, Caroline, David and Elaine are all different ages.
The sum of their ages is 110.
Ashley is the oldest and David is the youngest at 19.
Brian has the median age and he is younger than Caroline, who has the mean age.
Work out the age of each person.
Found 2 solutions by solver91311, ankor@dixie-net.com:
Answer by solver91311(24713)   (Show Source):
You can put this solution on YOUR website!
If B is the median, then two of the others must be older and two must be younger. A is one of the older because she is the oldest of the 5, and C is older because that fact is given. That means that E is second to the youngest because D is youngest.
So we have them in order of age from youngest to oldest:
D E B C A
Since the sum of their ages is 110 and C is the mean age, C is 110 divided by 5, or 22.
Since D is 19 and they are all different ages, E and B must be 20 and 21 respectively.
The sum of the ages of D, E, B, and C is 82. 110 minus 82 is 28. Therefore:
D is 19
E is 20
B is 21
C is 22
A is 28
John
My calculator said it, I believe it, that settles it
Answer by ankor@dixie-net.com(22740)  (Show Source):
You can put this solution on YOUR website! Ashley, Brian, Caroline, David and Elaine are all different ages.
The sum of their ages is 110.
Ashley is the oldest and David is the youngest at 19.
Brian has the median age and he is younger than Caroline, who has the mean age.
Work out the age of each person.
:
Find Caroline's age who is the mean
 = 22 yrs
:
The ages from oldest to youngest using the information given
A - C(22) - B - E - D(19)
It has to be
A - C(22) - B(21) - E(22) - D(19)
Find A
A = 110 - 22 - 21 - 20 - 19
A = 28 yrs
:
Ashley is 28
Brian is 21
Caroline is 22
Elaine is 20
Davide is 19
|
|
|
| |
