SOLUTION: Please help me solve this equation:Daniel is three times as old as kathryn. seven years ago, daniel was five times as old as kathryn. How are old they?
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Question 1038595: Please help me solve this equation:Daniel is three times as old as kathryn. seven years ago, daniel was five times as old as kathryn. How are old they? Found 2 solutions by josmiceli, ikleyn:Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! Let = Daniel's age now
Let = Kathryn's age now
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(1)
(2)
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This is 2 equations and 2 unknowns,
so it's solvable
Substitute (1) into (2)
(2)
(2)
(2)
(2)
(2)
and
(1)
(1)
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Daniel is 42
Kathryn is 14
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check:
(2)
(2)
(2)
(2)
OK
You can put this solution on YOUR website! . Please help me solve this equation:Daniel is three times as old as kathryn. seven years ago, daniel was five times as old as kathryn. How are old they?
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D = 3K (1) (Daniel is three times as old as kathryn)
D-7 = 5*(K-7) (2) (Seven years ago . . . )
Substitute the expression (1) for D into (3).
Then solve the single equation for K.
It is how all (almost all) age problems are solved.