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Question 1038417: X+2y-2=3
3x-y+2z=2
2x-2y+3z=2
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! X+2y-2=3 --> x+2y = 5 --> x = -2y+5
3x-y+2z=2
2x-2y+3z=2
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Sub for x in the 2nd & 3rd eqns
3(-2y+5) - y + 2z = 2 --> -7y + 2z = -13
2(-2y+5) -2y + 3z = 2 --> -6y + 3z = -8
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-7y + 2z = -13 times 3 --> -21y + 6z = -39
-6y + 3z = -8 times 2 --> -16y + 6z = -16
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-21y + 6z = -39
-16y + 6z = -16
----------------------- Subtract
5y = -23
y = -23/5
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-6y + 3z = -8
138/5 + 3z = -8
3z = -178/5
z = -178/15
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x = -2y + 5
z = -21/5
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