SOLUTION: Find a trig function given the max of (8am,20) and the min of (2am,10)

Algebra ->  Trigonometry-basics -> SOLUTION: Find a trig function given the max of (8am,20) and the min of (2am,10)      Log On


   



Question 1038320: Find a trig function given the max of (8am,20) and the min of (2am,10)
Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!

Let the function be

y+=+A%2Asin%28bx%2Bc%29%2Bd 

[We use capital A here to avoid conflicting notation with
small "a" used here for some value that has nothing to do
with amplitude, which is usually |a| in other problems but 
here the amplitude will be |A|.  I have no idea why the 
author of your problem would have put in the "am" anyway,
since it just clutters the problem.  He should have given 
points (8,20) and (2,10).  But I'll clutter the problem with
the nonsensical "am", since he did.]

The function has max at point where bx%2Bc+=+pi%2F2 
                                    bx+=pi%2F2-c
                                    x+=+%28pi%2F2-c%29%2Fb
                                    x+=+%28pi-2c%29%2F%282b%29

Since we are given the max at (8am,20), that's where x = 8am,

So    8am+=+%28pi-2c%29%2F%282b%29
      16abm+=+pi-2c
     
and where y = 20, that's where

y+=+A%2Asin%28bx%2Bc%29%2Bd
20+=+A%2Asin%28pi%2F2%29%2Bd
20+=+A%2A1%2Bd
A%2Bd=20

========================

y+=+A%2Asin%28bx%2Bc%29%2Bd [Use capital A to avoid conflicting notation]

has min at point where bx%2Bc+=+3pi%2F2 
                       bx+=3pi%2F2-c
                       x+=+%283pi%2F2-c%29%2Fb
                       x+=+%283pi-2c%29%2F%282b%29

Since given the min at (2am,10), that's where x = 2am,

So    2am+=+%283pi-2c%29%2F%282b%29
      4abm+=+3pi-2c
     
and where y = 10, that's where

y+=+A%2Asin%28bx%2Bc%29%2Bd
10+=+A%2Asin%283pi%2F2%29%2Bd
10+=+A%2A%28-1%29%2Bd
A-d=10

So we have the two systems of equations:

system%2816abm+=+pi-2c%2C4abm+=+3pi-2c%29 

and

system%28A%2Bd=20%2CA-d=10%29

From the first system:

system%2816abm+=+pi-2c%2C4abm+=+3pi-2c%29

Multiply the second by -4

system%2816abm+=+pi-2c%2C-16abm+=+-12pi%2B8c%29

Adding the equations gives;

0=4pi%2B6c
-6c=4pi
c=-4pi%2F6
c=-2pi%2F3

Substituting in 4abm = 3pi-2c

4abm+=+3pi-2c
4abm+=+3pi-2%282pi%2F3%29
4abm+=+3pi-4pi%2F3
12abm+=+9pi-4pi
12abm=5pi
b=5pi%2F%2812am%29

From the second system:

system%28A%2Bd=20%2CA-d=10%29

Adding them gives

2A=30
A=15

Subtracting them gives"

2d=10
d=5

So the equation

y+=+A%2Asin%28bx%2Bc%29%2Bd

becomes

y+=+15%2A%28expr%28sin%285pi%2F%2812am%29%29x%2Bexpr%282pi%2F3%29%5E%22%22%29%29%2B5

Edwin