Question 1038242: Roberto invested some money at 8%, and then invested $2000 more than twice this amount at 9%. His total annual income from the two investments was $3560. How much was invested at 9%?
The answer choices are A)$28,000 B)$2,800 C)$26,000 D)$6,000
I can never remember where to plug in which numbers. Could you please help me solve this?
Answer by jorel555(1290) (Show Source):
You can put this solution on YOUR website! Let n be the amount invested at 8%. Then
.08n+.09(2n+2000)=3560
.08n+.18n+180=3560
.26n=3380
n=3380/.26=$13000 invested at 8%, $28000 invested at 9%!!!!!!!!!!!!
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