Question 1038160: Elsa and Alvin are best friends and share a pet hummingbird called Sandy. Sandy loves to sing to both of them, and when they're apart she has a hard time deciding where to sing! One day after she had been staying at Elsa's, the children left their homes riding their bike toward each other. The homes are 13 miles apart, Elsa rides at 7mph and Alvin rides at 6mph. As soon as Elsa left home,Sandy started flying from Elsa to Alvin at 10mph. As soon as she reached Alvin, she change her mind and flying back to Elsa, and so on and so forth... How far did Sandy fly by the time the friends meet?
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! The homes are 13 miles apart, Elsa rides at 7mph and Alvin rides at 6mph.
As soon as Elsa left home,Sandy started flying from Elsa to Alvin at 10mph.
As soon as she reached Alvin, she change her mind and flying back to Elsa, and so on and so forth...
How far did Sandy fly by the time the friends meet?
let t = time it took E to meet A.
When they meet, the sum of their distances is 13 mi
Write a distance equation, dist = speed * time
7t + 6t = 13
13t = 13
t = 1 hr
:
The bird was in the air for 1 hr flying at 10 mph
The bird flew 10 miles
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