SOLUTION: acos₃x+3acosxsin₂x=m and asin₃x+3acos₂xsinx=n then (m+n)⅔+(m−n)⅔ is equal to
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-> SOLUTION: acos₃x+3acosxsin₂x=m and asin₃x+3acos₂xsinx=n then (m+n)⅔+(m−n)⅔ is equal to
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