Question 1038058: The Green Company produces solution bags. There are 3 inspectors assigned to visually check for defects. The inspectors differ in accuracy and speed. A inspects 25% of the bags each day and his accuracy rate is 92%. B inspects 45% of the bags and his accuracy rate is 95%. C inspects 30% of the bags and his accuracy rate is 96%.
1-4
1.Define the event.
2.Using events, write probabilities given in problem.
3. At the end of the day, a bag is picked at random. What is the probability that is was incorrectly inspected?
4. Given #3, what is the probability that it had been inspected by A?
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! ======Bags correct===bags incorrect====Total
A--------460---------------40--------------500
B--------855---------------45--------------900
C--------576---------------24--------------600
---------1891--------------109-------------2000
Tables make these a lot easier. I picked 2000 to avoid fractions.
For the first question, one can define probability a random bag is done by A and is incorrect. It is 4%
A random bag has a 5.45% chance of being incorrectly inspected., 109/2000
Given that a bag was incorrectly inspected, the probability it was inspected by A is 40/109=36.7%
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