SOLUTION: An airplane leaves Tacoma International Airport at a constant speed of 450 km per hour, at a bearing of S55 degrees W. How far west of the airport is the airplane after 2 hours? Dr

Algebra ->  Trigonometry-basics -> SOLUTION: An airplane leaves Tacoma International Airport at a constant speed of 450 km per hour, at a bearing of S55 degrees W. How far west of the airport is the airplane after 2 hours? Dr      Log On


   

Question 1038029: An airplane leaves Tacoma International Airport at a constant speed of 450 km per hour, at a bearing of S55 degrees W. How far west of the airport is the airplane after 2 hours? Draw a diagram.
D=RT
D=450(2)=900
Sin55/1 = W/900
900(Sin55) = W
900(0.819152) = W
737.237 = W
737 = W
I feel I am on the right track but would like to make sure.
Thank you

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
You're correct.
~ 737 kms