SOLUTION: The height of a triangle is One inch more than twice its base. The Area
is 18 inches squared. Find the dimensions (base and height) of the triangle.
Set up and solve using Algebr
Algebra ->
Polynomials-and-rational-expressions
-> SOLUTION: The height of a triangle is One inch more than twice its base. The Area
is 18 inches squared. Find the dimensions (base and height) of the triangle.
Set up and solve using Algebr
Log On
Question 1038016: The height of a triangle is One inch more than twice its base. The Area
is 18 inches squared. Find the dimensions (base and height) of the triangle.
Set up and solve using Algebraic Equation.
This is what I started with and then it became a mess:(
h= height, b=base
A= 1/2 bh
18=1/2x(2x+1) multiply both sides by 2
18=2(2)+1=5 ?
Thank you Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! The height of a triangle is One inch more than twice its base. The Area
is 18 inches squared. Find the dimensions (base and height) of the triangle.
Set up and solve using Algebraic Equation.
------------
Area = b*h/2 = 18
b*h = 36
h = 2b + 1
b*(2b+1) = 36
2b^2 + b - 36 = 0
(2b+9)*(b-4) = 0
b = 4
h = 9
------------
Ignore the negative solution.
