SOLUTION: Level 1, General Polynomials, Degree 2 Write your answer in the form (as + b) (cs +d) .... (es +f) New Problem, Factor: 15 s2 - 19 s + 6

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Level 1, General Polynomials, Degree 2 Write your answer in the form (as + b) (cs +d) .... (es +f) New Problem, Factor: 15 s2 - 19 s + 6       Log On


   



Question 103800: Level 1, General Polynomials, Degree 2
Write your answer in the form (as + b) (cs +d) .... (es +f)
New Problem, Factor:

15 s2 - 19 s + 6

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Solved by pluggable solver: Factoring using the AC method (Factor by Grouping)


Looking at the expression 15s%5E2-19s%2B6, we can see that the first coefficient is 15, the second coefficient is -19, and the last term is 6.



Now multiply the first coefficient 15 by the last term 6 to get %2815%29%286%29=90.



Now the question is: what two whole numbers multiply to 90 (the previous product) and add to the second coefficient -19?



To find these two numbers, we need to list all of the factors of 90 (the previous product).



Factors of 90:

1,2,3,5,6,9,10,15,18,30,45,90

-1,-2,-3,-5,-6,-9,-10,-15,-18,-30,-45,-90



Note: list the negative of each factor. This will allow us to find all possible combinations.



These factors pair up and multiply to 90.

1*90 = 90
2*45 = 90
3*30 = 90
5*18 = 90
6*15 = 90
9*10 = 90
(-1)*(-90) = 90
(-2)*(-45) = 90
(-3)*(-30) = 90
(-5)*(-18) = 90
(-6)*(-15) = 90
(-9)*(-10) = 90


Now let's add up each pair of factors to see if one pair adds to the middle coefficient -19:



First NumberSecond NumberSum
1901+90=91
2452+45=47
3303+30=33
5185+18=23
6156+15=21
9109+10=19
-1-90-1+(-90)=-91
-2-45-2+(-45)=-47
-3-30-3+(-30)=-33
-5-18-5+(-18)=-23
-6-15-6+(-15)=-21
-9-10-9+(-10)=-19




From the table, we can see that the two numbers -9 and -10 add to -19 (the middle coefficient).



So the two numbers -9 and -10 both multiply to 90 and add to -19



Now replace the middle term -19s with -9s-10s. Remember, -9 and -10 add to -19. So this shows us that -9s-10s=-19s.



15s%5E2%2Bhighlight%28-9s-10s%29%2B6 Replace the second term -19s with -9s-10s.



%2815s%5E2-9s%29%2B%28-10s%2B6%29 Group the terms into two pairs.



3s%285s-3%29%2B%28-10s%2B6%29 Factor out the GCF 3s from the first group.



3s%285s-3%29-2%285s-3%29 Factor out 2 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.



%283s-2%29%285s-3%29 Combine like terms. Or factor out the common term 5s-3



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Answer:



So 15%2As%5E2-19%2As%2B6 factors to %283s-2%29%285s-3%29.



In other words, 15%2As%5E2-19%2As%2B6=%283s-2%29%285s-3%29.



Note: you can check the answer by expanding %283s-2%29%285s-3%29 to get 15%2As%5E2-19%2As%2B6 or by graphing the original expression and the answer (the two graphs should be identical).