|
Question 1037960: One number is one less than twice the other. Their product is 120.
Find the numbers (should have two sets of answers.) Set up using an Algebraic Equation and use a complete sentence.
Am I on the right path?
x= 2x+1
y= the other number
y=2x-1
(y)(x)=120
y(2x-1)=120
2x^2-x=120
(2x+15)(x-8)=0
x=8
y=15
The two numbers that are one numberless than twice the other are 8 and 15.
Thank you
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! One number is one less than twice the other. Their product is 120.
Find the numbers (should have two sets of answers.) Set up using an Algebraic Equation and use a complete sentence.
Am I on the right path?
x= 2x+1 ******************** That's not right.
y= the other number
y=2x-1
(y)(x)=120
y(2x-1)=120
2x^2-x=120
(2x+15)(x-8)=0
x=8
y=15
The two numbers that are one numberless than twice the other are 8 and 15.
Thank you
==============
Check your answers.
15 is 2*8 - 1, so that's OK.
The product is 120. --> 8 & 15 is a solution.
============
do it like this:
y = 2x - 1
x*y = 120
Sub for y
x*(2x - 1) = 120
2x^2 - x - 120 = 0
(x - 8)*(2x + 15) = 0
x = 8, y = 15
=============
x = -7.5, y = -16
---
-16 = 2*(-7.5) - 1 (the 2nd solution)
|
|
|
| |
