SOLUTION: Find the limits using L’Hospital’s Rule where appropriate. c) lim (x^10 - 2x + 1) / (x^4-1) x→1 d) lim (5^x + 2x - 1) / (2^x - 1) x→0 I appreciate the

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Find the limits using L’Hospital’s Rule where appropriate. c) lim (x^10 - 2x + 1) / (x^4-1) x→1 d) lim (5^x + 2x - 1) / (2^x - 1) x→0 I appreciate the       Log On


   

Question 1037918: Find the limits using L’Hospital’s Rule where appropriate.
c) lim (x^10 - 2x + 1) / (x^4-1)
x→1
d) lim (5^x + 2x - 1) / (2^x - 1)
x→0
I appreciate the help :)
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
c) . The second limiting expression was obtained by differentiating both numerator and denominator. The initial indeterminate form was 0/0.
d) .