SOLUTION: For a 200km journey if a van had increased its speed by 10 km/h, the journey would have been completed in 1 hour less. What was the original speed of the Van for the journey?

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Question 1037742: For a 200km journey if a van had increased its speed by 10 km/h, the journey would have been completed in 1 hour less. What was the original speed of the Van for the journey?
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39617) (Show Source):
You can put this solution on YOUR website!
Travel Rates Rule is RT=D to relate RATE, TIME, DISTANCE.

RATE TIME DISTANCE AS DONE r t 200 IF r+10 t-1 200

The exercise is similar to another one and the method would be the same.
See this as an instructive example: https://www.algebra.com/algebra/homework/quadratic/Quadratic_Equations.faq.question.1037668.html

Answer by ikleyn(52782) (Show Source):
You can put this solution on YOUR website!
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For a 200 km journey if a van had increased its speed by 10 km/h, the journey would have been completed in 1 hour less.
What was the original speed of the Van for the journey?
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Let "v" be the original speed (in ) which is under the question. In this problem, you are given the difference of times. So, your equation should be based on this difference of times. One time is = , which is greater. Another time is = ; it is shorter. Their difference is 1 hour. Hence, the equation is = 1. To solve it, first multiply both sides by v*(v+10) to rid of the denominators. Then collect like terms and simplify. You will get a quadratic equation. Solve it by any appropriate method (factorization or the the quadratic formula). Please complete it on your own.