SOLUTION: Given {{{cos(theta)}}} = -{{{7/25}}} and 180° < {{{theta}}} < 270°; find the exact value of {{{sin(theta/2)}}}.

Algebra ->  Trigonometry-basics -> SOLUTION: Given {{{cos(theta)}}} = -{{{7/25}}} and 180° < {{{theta}}} < 270°; find the exact value of {{{sin(theta/2)}}}.      Log On


   



Question 1037376: Given cos%28theta%29 = -7%2F25 and 180° < theta < 270°; find the exact value of sin%28theta%2F2%29.
Answer by ikleyn(52802) About Me  (Show Source):
You can put this solution on YOUR website!
.
Given cos%28theta%29 = -7%2F25 and 180° < theta < 270°; find the exact value of sin%28theta%2F2%29.
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Use the formula of Trigonometry

sin%5E2%28theta%2F2%29 = %281-cos%28theta%29%29%2F2

(se the lesson Trigonometric functions of half argument in this site).

You will have

sin%28theta%2F2%29 = sqrt%28%281-%28-7%2F25%29%5E2%29%2F2%29 = sqrt%28%281+-+49%2F625%29%2F2%29 = sqrt%28%28625-49%29%2F%282%2A625%29%29 = sqrt%28576%2F%282%2A625%29%29 = 24%2F%28sqrt%282%29%2A25%29 = %2812%2Asqrt%282%29%29%2F25.

The sign "+" was chosen at the square root since the angle theta%2F2 lies in the 2-nd quadrant.

For similar problems see the lessons
    - Calculating trigonometric functions of angles
    - Advanced problems on calculating trigonometric functions of angles
in this site.