SOLUTION: Given {{{cos(theta)}}} = -{{{7/25}}} and 180° < {{{theta}}} < 270°; find the exact value of {{{sin(theta/2)}}}.
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-> SOLUTION: Given {{{cos(theta)}}} = -{{{7/25}}} and 180° < {{{theta}}} < 270°; find the exact value of {{{sin(theta/2)}}}.
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Given = - and 180° < < 270°; find the exact value of .
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Use the formula of Trigonometry
=
(se the lesson Trigonometric functions of half argument in this site).
You will have
= = = = = = .
The sign "+" was chosen at the square root since the angle lies in the 2-nd quadrant.