Question 1037325: Referring to the information below, what is the number of calls that the doctor's answering service could expect to receive for him during lunch hour?
The probabilities that a doctor's answering service will receive 0, 1, 2, 3, 4, 5, 6, or 7 calls for him during lunch hour are, respectively, 0.001, 0.006, 0.022, 0.052, 0.091, 0.128, 0.149, and 0.551.
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! It is the sum of the products of the random variable times the probability.
0*0.001=0.000
1*0.006=0.006
2*0.022=0.044
3*0.052=0.156
4*0.091=0.364
5*0.128=0.640
6*0.149=0.894
7*0.551=3.857
Total is 5.961 or nearly 6 calls is E(x).
|
|
|
