Question 1037285: A plane leaves Chicago headed for Los Angeles at 550 mph. One hour later, a second plane leaves Los Angeles headed for Chicago at 630 mph. If the air route from Chicago to Los Angeles is 1800 miles, how long will it take (after the first plane takes off) for the first plane to pass the second plane? (Round your answer to two decimal places.)
Hours?
Miles?
I got 7.87 for hours and 2529 for miles. Its wrong and i cant for the life of me figure out my mistake
Found 2 solutions by Alan3354, MathTherapy:
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! A plane leaves Chicago headed for Los Angeles at 550 mph. One hour later, a second plane leaves Los Angeles headed for Chicago at 630 mph. If the air route from Chicago to Los Angeles is 1800 miles, how long will it take (after the first plane takes off) for the first plane to pass the second plane? (Round your answer to two decimal places.)
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The 1st is 550 miles away when the 2nd takes off.
The 2nd gains on the 1st at 80 mi/hr (630 - 550)
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550/80 = 6.88 hours
+ the 1st hour --> 7.88 hours
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In that time, the 1st plane would fly 3781 miles, past LA.
Kind of a trick question.
The 2nd plane catches up at LAX in 1800/630 hours = 2.86 + 1 = 3.86 hours.
IDK if it passes the 1st plane.
Answer by MathTherapy(10551)  (Show Source):
You can put this solution on YOUR website!
A plane leaves Chicago headed for Los Angeles at 550 mph. One hour later, a second plane leaves Los Angeles headed for Chicago at 630 mph. If the air route from Chicago to Los Angeles is 1800 miles, how long will it take (after the first plane takes off) for the first plane to pass the second plane? (Round your answer to two decimal places.)
Hours?
Miles?
I got 7.87 for hours and 2529 for miles. Its wrong and i cant for the life of me figure out my mistake
Let time the 1st plane (Chicago to LA) takes to get to “meeting” point, be T
Then time the 2nd plane (LA to Chicago) takes to get to “meeting” point is: T – 1
Distance 1st plane traveled to get to meeting point: 550T
Distance 2nd plane traveled to get to meeting point: 630(T – 1)
We then get the following DISTANCE equation: 550T + 630(T – 1) = 1,800
550T + 630T – 630 = 1,800
1,180T = 1,800 + 630
1,180T = 2,430
T, or time it took for 1st plane to get to “meeting” point = 
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