SOLUTION: 5sin^2 90deg + 2cos^2 270deg - tan 360deg

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Question 1037230: 5sin^2 90deg + 2cos^2 270deg - tan 360deg
Answer by ikleyn(52943) About Me  (Show Source):
You can put this solution on YOUR website!
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5sin^2(90°) + 2cos^2(270°) - tan(360°)
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sin(90°) = 1; cos(270°) = 0; tan(360°) = 0.

Therefore, 5sin^2(90°) + 2cos^2(270°) - tan(360°) = 5*1 + 2*0 -0 = 5.