SOLUTION: A tank is 80cm in length, 50cm in width and 60cm in height. It is half filled with water. A solid cylinder with base radius 20cm and height 50cm is fully immersed in water and no w
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Question 1037143: A tank is 80cm in length, 50cm in width and 60cm in height. It is half filled with water. A solid cylinder with base radius 20cm and height 50cm is fully immersed in water and no water is absorbed. Find the increase of the depth of the water (pi=3.14) to 1dp.
How do I do this, thanks. Answer by ikleyn(52787) (Show Source):
You can put this solution on YOUR website! .
A tank is 80 cm in length, 50 cm in width and 60 cm in height. It is half filled with water.
A solid cylinder with base radius 20 cm and height 50 cm is fully immersed in water and no water is absorbed.
Find the increase of the depth of the water (pi=3.14) to 1 dp.
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The volume of the water in the tank (before immersing) is
= = 80*50*(60/2) , where h = 30 cm = cm is the water level before immersing.
Let H be the water height after immersing. The volume of water didn't change, so we have this equation
80*50*30 = , where r and are dimensions of the cylinder.
Divide both sides by 80*50 and get
H = 30 + .
You make calcs.
