SOLUTION: At a bus stop 20 students were standing in four groups. The first group contained
four students more than the second. The second group contained one student less
than the third.
Algebra ->
Average
-> SOLUTION: At a bus stop 20 students were standing in four groups. The first group contained
four students more than the second. The second group contained one student less
than the third.
Log On
Question 1037136: At a bus stop 20 students were standing in four groups. The first group contained
four students more than the second. The second group contained one student less
than the third. The fourth group contained twice as many students as the second
group. How many students were in each group? Answer by Cromlix(4381) (Show Source):
You can put this solution on YOUR website! Hi there,
Make the Third group
contain 'x' students.
Second group contains
1 student less than the 3rd.
= (x - 1)
The First group contains 4
more students than the 2nd
= (x - 1) + 4
= x + 3
The Fourth group contains
twice as many students as
the 2nd group.
= 2(x - 1)
= 2x - 2
................
First group = (x + 3)
Second group = (x - 1)
Third group = x
Fourth group = 2x - 2
Add all the groups up:
(x + 3) + (x - 1) + (x) + (2x - 2)
x + 3 + x - 1 + x + 2x - 2 = 20
Collect like terms:
5x = 20
x = 4
.................
First group = (x + 3)= 7
Second group = (x - 1)= 3
Third group = x = 4
Fourth group = 2x - 2 = 6
..............
7,3,4 and 6.
Hope this helps:-)
