SOLUTION: Hi, I have a maths test tomorrow and i am pretty much sweet except for one thing. Questions like: If log(base7)2=0.36 and log(base7)=0.56, find: (a) log(base7)6 (Now this one i

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Hi, I have a maths test tomorrow and i am pretty much sweet except for one thing. Questions like: If log(base7)2=0.36 and log(base7)=0.56, find: (a) log(base7)6 (Now this one i      Log On


   



Question 1037131: Hi,
I have a maths test tomorrow and i am pretty much sweet except for one thing.
Questions like:
If log(base7)2=0.36 and log(base7)=0.56, find:
(a) log(base7)6 (Now this one is easy i.e log(base7)2 x log(base7)3 = 0.36+0.56 = 0.92
But i don't have a definite thought process going on. Could you possibly give me a set method? Use log(base7)14 as an example aswell please.
Thanks heaps
Matt

Found 3 solutions by addingup, ikleyn, MathTherapy:
Answer by addingup(3677) About Me  (Show Source):
You can put this solution on YOUR website!
log_7(14)
= log(14)/log(7)
1.3562
i'm not sure this is what you were looking for. But you'd do the others the same way. For example:
log_7(2) = log(2)/log(7) = 0.356207

Answer by ikleyn(52794) About Me  (Show Source):
You can put this solution on YOUR website!
.
Hi,
I have a maths test tomorrow and i am pretty much sweet except for one thing.
Questions like:
If log(base7)2=0.36 and log(base7)=0.56, find:         <<<---  This line is written incorrectly.
(a) log(base7)6 (Now this one is easy i.e log(base7)2 x log(base7)3 = 0.36+0.56 = 0.92
But i don't have a definite thought process going on. Could you possibly give me a set method? Use log(base7)14 as an example as well please.
Thanks heaps

Matt
~~~~~~~~~~~~~~~~~~~~~~~~~~

We all would be glad to answer your question, had it be written correctly.


Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

Hi,
I have a maths test tomorrow and i am pretty much sweet except for one thing.
Questions like:
If log(base7)2=0.36 and log(base7)=0.56, find:
(a) log(base7)6 (Now this one is easy i.e log(base7)2 x log(base7)3 = 0.36+0.56 = 0.92
But i don't have a definite thought process going on. Could you possibly give me a set method? Use log(base7)14 as an example aswell please.
Thanks heaps
Matt
log+%287%2C+2%29+=+0.36            log+%287%2C+3%29+=+.56
log+%287%2C+6%29
log+%287%2C+%282+%2A+3%29%29
log+%287%2C+2%29+%2B+log+%287%2C+3%29+=+0.36+%2B+.56+=+.92

log+%287%2C+14%29
log+%287%2C+%282+%2A+7%29%29