SOLUTION: A vessel contains a mixture of 16 litres of milk and 8 litres of water and a second vessel contains a mixture of 16 litres of milk and 5 litres of water. How much of the mixture of
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Question 1037120: A vessel contains a mixture of 16 litres of milk and 8 litres of water and a second vessel contains a mixture of 16 litres of milk and 5 litres of water. How much of the mixture of milk and water should be taken from the first and the second vessels respectively and placed in a third vessel, so that the third vessel may contain a mixture of 20 litres of milk and 8 litres of water? Found 2 solutions by jorel555, ankor@dixie-net.com:Answer by jorel555(1290) (Show Source):
You can put this solution on YOUR website! If the first vessel is 16 litres of milk to 8 litres of water, then it is 16/24 milk, or .67 milk. Similarly, the second mix is 16/21 milk, or .762 milk. We want 20 litres of mile out of 28. Let n= amount of first mixture. Then:
.67n+.762(28-n)=20
.67n+21.336-.762n=20
.092n=1.336
n=1.336/.092=14.52 litres of the first mixture, and 13.47 litres of the second!!!!!!!!!!!!!
You can put this solution on YOUR website! A vessel contains a mixture of 16 litres of milk and 8 litres of water and a second vessel contains a mixture of 16 litres of milk and 5 litres of water.
How much of the mixture of milk and water should be taken from the first and the second vessels respectively and placed in a third vessel, so that the third vessel may contain a mixture of 20 litres of milk and 8 litres of water?
:
the first mixture, contains a total of 16+8 = 24 liters
it will be 16/24 or 2/3 milk
the second mixture, contains a total of 16+5 = 21 liters
it will be 16/21 milk
the resulting mixture will be a total of 20+8 = 28 liters
it will be 20/28 or 5/7 milk
:
let a = amt of the 1st mixture required
the resulting mixture will have 20 liters, therefore
(20 - a) = amt of the 2nd mixture required
:
A mixture equation a + (20 - a) = (20)
multiply by 21, cancel the denominators, and you have
7(2a) + 16(20-a) = 3(5(20))
14a + 320 - 16a = 300
14a - 16a = 300 - 320
-2a = -20
a = -20/-2
a = +10 liters of mixture 1
then
20 - 10 = 10 liters of mixture 2
:
:
Check this out, see if the amt of water checks out
A is 1/3 water or 3.33 liters
B is 5/21 water or 2.38 liters\
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resulting amt has 2/7 water or 5.71 liters, the sum.
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