SOLUTION: The perimeter of a rectangular field is 320 yd. The length is 60 yd longer than the width. Find the dimensions. a). The smaller of the two sides is _ yd? b). And the larger

Algebra ->  Trigonometry-basics -> SOLUTION: The perimeter of a rectangular field is 320 yd. The length is 60 yd longer than the width. Find the dimensions. a). The smaller of the two sides is _ yd? b). And the larger      Log On


   

Question 1037096: The perimeter of a rectangular field is 320 yd. The length is 60 yd longer than the width. Find the dimensions.
a). The smaller of the two sides is
_ yd?
b). And the larger is ?
Answer by jorel555(1290) About Me  (Show Source):
You can put this solution on YOUR website!
Let w=width; Length,l, equals w+60.
2w+2(w+60)=320
2w+2w+120=320
4w=200
w=50 yds.
l=110 yds. !!!!!!!!!!!!!!!!!!!!!!!!