SOLUTION: Divide 180 in two parts such that the first part is 12 less than twice the second part.
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Question 1037005
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Divide 180 in two parts such that the first part is 12 less than twice the second part.
Answer by
jorel555(1290)
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Let the second part be n. Then the first part is 2n-12;
n+2n-12=180
3n=192
n=64
2n-12=116
The first part is 116, the second is 64!!!!!!!!!!