SOLUTION: For x² - 4xy - 2y² - 6 = 0, find Θ, the angle of rotation about the origin, to the nearest degree.

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Question 1036875: For x² - 4xy - 2y² - 6 = 0, find Θ, the angle of rotation about the origin, to the nearest degree.

Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!

x² - 4xy - 2y² - 6 = 0

The angle of rotation theta of the graph 

Ax² + Bxy + Cy² + Dx + Ey + F = 0

necessary to transform it into an equation in x' 
and y' which contains no term in x'y'

is calculated by tan%282theta%29=B%2F%28A-C%29 or 45° or pi%2F4
if A = C

Your equation is

x² - 4xy - 2y² - 6 = 0

In this case A=1, B=-4, C=-2, D=0, E=0, F = -6

Substituting in

tan%282theta%29=B%2F%28A-C%29
tan%282theta%29=%28-4%29%2F%281-%28-2%29%29
tan%282theta%29=%28-4%29%2F%281%2B2%29
tan%282theta%29=-4%2F3
Choosing the smallest positive angle:
2theta=2.214297436 or 2theta=%22126.8698976%B0%22
theta=1.107148718 or theta=%2263.43494882%B0%22

Edwin