SOLUTION: Three times the ages of Philip is 4 more then the ages of Isaac in 3 years the sum of their ages will be 30 years. Find their present ages.
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-> SOLUTION: Three times the ages of Philip is 4 more then the ages of Isaac in 3 years the sum of their ages will be 30 years. Find their present ages.
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You can put this solution on YOUR website! let p = P's present age
let i = I's age
:
Write an equation for each statement:
Three times the ages of Philip is 4 more then the age of Isaac
3p = i + 4
3p - i = 4
in 3 years the sum of their ages will be 30 years.
(p+3) + (i+3) = 30
p + i + 6 = 30
p + i = 30 - 6
p + i = 24
Use elimination on these two equations
3p - i = 4
p + i = 24
-----------------addition eliminates i, find p
4p = 28
p = 28/4
p = 7 yrs is P's present age
:
Use 3p = i + 4 to find p
3(7) = i + 4
21 = i + 4
21 - 4 = i
17 = i
i = 17 yrs is I's age
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you can confirm these solutions in the 2nd statement
" in 3 years the sum of their ages will be 30 years."
