Question 1036783: In a test of the effectiveness of garlic for lowering cholesterol, 45 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes in their levels of LDL cholesterol (in mg/dL) have a mean of 3.4 and a standard deviation of 18.3.
Construct a 95% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol?
What is the confidence interval estimate of the population mean μ?
Thank You for your help.
Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! This is a paired t-test
Ho:mean =0
Ha:mean ne0.
alpha=0.05
test stat is t, df=44 critical value abs(t)>2.01
t is mean over SE
calculation: SE is 18.3/sqrt (45)=2.73; mean/SE=1.25
Fail to reject Ho
CI is mean +/- t*SE=3.4 +/-2.01*2.73 and the product is 5.49.
The interval is (-2.09,8.89). The interval contains 0, so 0, or no change, is a plausible value, and there is no convincing evidence that garlic affects LDL cholesterol levels.
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