Question 1036719: The sum of the ages of John and Shane before six years was 13 years. The sum of their ages after 8 years will be ________.
Thank you !!!!
Found 4 solutions by josgarithmetic, ikleyn, MathTherapy, Vixiachase:
Answer by josgarithmetic(39618)   (Show Source):
Answer by ikleyn(52788)  (Show Source):
You can put this solution on YOUR website! .
The sum of the ages of John and Shane before six years was 13 years. The sum of their ages after 8 years will be ________.
Thank you !!!!
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You are given that (j-6) + (s-6) = 13.
Hence, j + s = 13 + 6 + 6 = 25.
You are asked about
(j+8) + (s+8).
It is 25 + 8 + 8 = 41.
Answer. 41.
It is not about solving equations.
You do not need to solve equations.
It is about estimation of the value.
Answer by MathTherapy(10552)  (Show Source):
You can put this solution on YOUR website!
The sum of the ages of John and Shane before six years was 13 years. The sum of their ages after 8 years will be ________.
Thank you !!!!
Let John's and Shane's ages, be J, and S, respectively
Then 6 years ago, we had: J + S - 2(6) = 13
J + S - 12 = 13
J + S = 13 + 12
J + S = 25
In 8 years, sum of ages, or J + S + 2(8), or J + S + 16
Since J + S = 25, then J + S + 16 becomes: 25 + 16, or 
Answer by Vixiachase(22)  (Show Source):
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