Question 1036568: If $80,000 is invested part at 8% and the rest at 10%, and the interest from one year is $7,800, how much was invested at 10%? Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! x invested at 8%
80000-x (the rest) invested at 10%
.08x+.10(80000-x)=7800
.08x+8000-.10x=7800
-.02x=-200
x=$10,000 which at 8% is $800
70,000 (ANSWER) of @10% is $7000.
they add to $7800.