SOLUTION: I am really having a hard time with this one. Been working on it for nearly 3 hours and cant seem to figure out how to make it work. Problem: r(t) is the position of a particle

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: I am really having a hard time with this one. Been working on it for nearly 3 hours and cant seem to figure out how to make it work. Problem: r(t) is the position of a particle       Log On


   



Question 1036508: I am really having a hard time with this one. Been working on it for nearly 3 hours and cant seem to figure out how to make it work.
Problem: r(t) is the position of a particle in the xy-plane at time t. Find an equation in x and y whose graph is the path of the particle. Then find the particle’s velocity and acceleration vectors at the given value of t.
+r%28t%29+=+e%5Et+i+%2B+%282%2F9%29+e%5E%282t%29+j+
where +t+=+ln3+
To find the Equation, I first organize it into a set:
[ +e%5Et+, +%282%2F9%29+e%5E%282t%29+ ]
Then I just plug in the value of t (ln3)
[ +e%5E%28ln3%29+, +%282%2F9%29+e%5E%282%28ln3%29%29+ ]
I then reconstruct the original problem with the new values:
+r%28t%29+=+e%5E%28ln3%29+i+%2B+%282%2F9%29+e%5E%282%28ln3%29%29+j+
+r%28ln3%29+=+e%5E%281.0986%29+i+%2B+%282%2F9%29+e%5E%282.1972%29+j+
then I change the i / j coordinates to x/y coordinates
+r%28ln3%29+=+e%5E%281.0986%29+x+%2B+%282%2F9%29e%5E%282.1972%29+y+
-----------------------------
As for velocity and acceleration, so far I have figured it like this:
Velocity:
[ +e%5Et+, +%282%2F9%29+e%5E%282t%29+ ]
[ +te+, +%284%2F9%29+e%5Et+ ]
+Velocity+=+tei+%2B+%284%2F9%29etj+
Acceleration:
[ +e+, +%284%2F9%29+te+]
+Acceleration+=+tei+%2B+%284%2F9%29+tej+
Am I taking the derivative correctly? As far as I know, e remains as e, even after the derivative, right?
thanks in advance

Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
I think you meant +r%28t%29+=+e%5Et%2A+i+%2B+%282%2F9%29+e%5E%282t%29%2A+j+, which is a vector-valued function.
Let x+=+e%5Et and y+=+%282%2F9%29+e%5E%282t%29 as they were meant to be.
Then after a simple substitution, you should get y=%282%2F9%29+%28e%5Et%29%5E2+=+%282%2F9%29x%5E2.
+Velocity+=+e%5Et%2Ai+%2B+%284%2F9%29e%5E%282t%29%2Aj+
+Acceleration+=+e%5Et%2Ai+%2B+%288%2F9%29e%5E%282t%29%2Aj+