SOLUTION: Bag A contains 3 red marbles and 2 green marbles. Bag B contains 5 green marbles only. one marble is randomly drawn from A and put into bag B.then one marble is randomly drawn from

Algebra ->  Probability-and-statistics -> SOLUTION: Bag A contains 3 red marbles and 2 green marbles. Bag B contains 5 green marbles only. one marble is randomly drawn from A and put into bag B.then one marble is randomly drawn from      Log On


   

Question 1036371: Bag A contains 3 red marbles and 2 green marbles. Bag B contains 5 green marbles only. one marble is randomly drawn from A and put into bag B.then one marble is randomly drawn from bag B.find the probability that the marble drawn from bag Bis
a. red
b. green
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
Let r%5BA%5D be the event where the ball drawn from bag A is red, g%5BA%5D the event where the ball drawn from bag A is green. we want to find p%28r%5BB%5D%29, the probability that the ball drawn from bag B is red.
==> p%28r%5BB%5D%29+=+p%28r%5BA%5D+and+r%5BB%5D%29+%2B+p%28g%5BA%5D+and+r%5BB%5D%29
=p(r%5BB%5D|r%5BA%5D)*p(r%5BA%5D) + p(r%5BB%5D|g%5BA%5D)*p(g%5BA%5D)
=(1/6)*(3/5) + 0*(2/5) = 1/10.
Therefore, p%28r%5BB%5D%29+=+1%2F10.
This also implies that p%28g%5BB%5D%29+=+9%2F10.