SOLUTION: Find g(0), g(-1), g(-4) and g(2/3) for g(x)= x over square root √ 1-x^2

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Question 1036353: Find g(0), g(-1), g(-4) and g(2/3) for g(x)= x over square root
√ 1-x^2
Found 2 solutions by Aldorozos, ikleyn:
Answer by Aldorozos(172) About Me  (Show Source):
You can put this solution on YOUR website!
0/any = 0
-1/sqrt0 doesn't exist
-4/sort 1-16 = -4/sqrt of -15 doesn't exist
2/3 divided by sqrt of one minus two thirds to the power two is 2/3 divided. Y square root of five over nine which is equal to two divided by square root of 5

Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.
0/any = 0.

-1%2Fsqrt%280%29 doesn't exist

-4%2Fsort%281-16%29 = -4%2Fsqrt%28-15%29 doesn't exist.

2%2F3 divided by sqrt%281+-%282%2F3%29%5E2%29 is 2%2F3 divided by sqrt%285%29%2F3.

So the final ratio is 2%2Fsqrt%285%29 = %282%2Asqrt%285%29%29%2F5.


This is written partly for the student and partly for the previous tutor to help him to learn writing formulas in this site.

To see the original "code", press the button "EDIT THIS SOLUTION" under my posting.