SOLUTION: Please help me to solve this - If a , b are the zeroes to f the polynomial p(x)=x^2-p(x+1)-c such that (a+1)(b+1)=0. What is the value of c

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Please help me to solve this - If a , b are the zeroes to f the polynomial p(x)=x^2-p(x+1)-c such that (a+1)(b+1)=0. What is the value of c      Log On


   

Question 1036258: Please help me to solve this - If a , b are the zeroes to f the polynomial p(x)=x^2-p(x+1)-c such that (a+1)(b+1)=0. What is the value of c
Found 2 solutions by robertb, ikleyn:
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
Let a,b be the zeroes of p(x).
p%28x%29+=+x%5E2-p%28x%2B1%29-c++=+x%5E2+-+px+-+p+-+c ==> -p = -(a+b) ==> p = a+b,
and
-p - c = ab.
Now (a+1)(b+1)= ab + a+b+1 =0 ==> -p-c + p + 1 = 0
==> c = 1, after simplifying.

Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.
Please help me to solve this - If a , b are the zeroes to f the polynomial p(x)=x^2-p(x+1)-c such that (a+1)(b+1)=0. What is the value of c
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Hello, the author,

It is not a good style to keep the same letter for the polynomial p(x) and for one of its coefficients.