AE = AB-EB = AB-DC = 213-185 = 28
tan(∠DAE) = = = =
∠DAE = 75.84236735°
tan(∠CAB) = = =
∠CAB = 27.52522574°
∠q = ∠DAE-∠CAB = 75.84236735°-27.52522574° = 48.31714161°
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∠f is an exterior angle to ΔAEF,
so it is the sum of the two remote interior angles of ΔAEF,
so ∠f = ∠CAE + ∠AEF = 27.52522574°+ 90° = 117.5252257°
Edwin