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Question 1036173: You also learned in class that one kilobyte of computer memory will hold about 2/3 of a page of typical text(without formatting). A typical book has about 400 pages. Can the 9-gig flash drive hold tens, hundreds, or thousands of such books?
Found 2 solutions by stanbon, Theo:
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! You also learned in class that one kilobyte of computer memory will hold about 2/3 of a page of typical text(without formatting). A typical book has about 400 pages. Can the 9-gig flash drive hold tens, hundreds, or thousands of such books?
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1 kilobyte = 1000 bytes
1 gigbyte = 1,000,000,000 bytes
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book = 400 pages = 400/(2/3) = 600 kilogytes
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# of books = 9,000,000,000/600 = 15 million books
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Cheers,
Stan H.
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Answer by Theo(13342)  (Show Source):
You can put this solution on YOUR website! you are given that one kilybote of computer memory will hold about 2/3 of a page of a typical text (without formatting).
a typical book has about 400 pages.
2/3 of a page is equal to one kilobyte of memory.
if you take 400 pages and divide them by 2/3 of a page, you will get 400 / (2/3) = 400 * 3/2 = 1200/2 = 600 * 2/3 of a page being contained in a 400 page book.
since 2/3 of a page is handled by one kilobyte of memory, then 600 * 2/3 of a page is equal to 600 kilobytes of memory.
this means that one book requires 600 kilobytes of memory.
1 gigabyte is equal to 1,000 megabytes which is equivalent to 1,000 kilobytes.
that means that 1 gigabyte is equal to 1,000 * 1000 = 1 million kilobytes.
so 9 gigabytes is equal to 9 million kilobytes.
since 1 book requires 600 kilobytes, then you divide 9 million by 600 and you get 15000 books that can fit into a 9 gigabyte flash storage device.
the 9 gigabyte flash storage device can handle thousands of 400 page books.
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