SOLUTION: From the equation, find the vertex, focus, directrix, and latus rectum.
{{{(y-4)^2 = -8(x+3)}}}
Please show me steps because i have been trying since yesterday and kept getti
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-> SOLUTION: From the equation, find the vertex, focus, directrix, and latus rectum.
{{{(y-4)^2 = -8(x+3)}}}
Please show me steps because i have been trying since yesterday and kept getti
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Question 1036048: From the equation, find the vertex, focus, directrix, and latus rectum.
Please show me steps because i have been trying since yesterday and kept getting my answers wrong. Thankyou! Answer by josgarithmetic(39617) (Show Source):
You can put this solution on YOUR website! That is a form which you could get if you were given the focus and directrix and then derived the equation shown. The process would have gone like any of these:
You can read some information directly from the equation which you have.
The vertex is (-3,4).
The negative coefficient on the x side tells you that this has a graph with horizontal symmetry axis and the parabola opens toward the left, and vertex is a rightmost point on the parabola.
A value p is the distance between the vertex and either the focus or directrix. You have 8=4p, which is what you learn in making the derivation. You can solve for p and determine the focus and the directrix.
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