SOLUTION: What number when multiplied by itself is 13 greater than the preceding number when it is multiplied by itself

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Question 1036042: What number when multiplied by itself is 13 greater than the preceding number when it is multiplied by itself
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
What kind of preceding number?

The number to multiplied by itself, x.
Some unspecified preceding number, n.
x%2Ax=13%2Bn%2An
x%5E2=n%5E2%2B13
x=sqrt%28n%5E2%2B13%29, but this should be x=0%2B-+sqrt%28n%5E2%2B13%29.

If your preceding number should be an integer, then you may want n=x-1. This will give the initial equation as x%5E2=%28x-1%29%5E2%2B13 and then you could solve this for x.


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You could accept the assumption I described, and you should be able to solve the resulting x%5E2=%28x-1%29%5E2%2B13 without trouble.