SOLUTION: The sum of the reciprocals of two consecutive positive integers is 17/12. Write an equation that can be used to find the two integers. What are the integers?

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Question 1035962: The sum of the reciprocals of two consecutive positive integers is 17/12. Write an equation that can be used to find the two integers. What are the integers?
Found 3 solutions by ikleyn, Theo, MathTherapy:
Answer by ikleyn(52803) About Me  (Show Source):
You can put this solution on YOUR website!
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The sum of the reciprocals of two consecutive positive integers is 17/12. Write an equation that can be used
to find the two integers. What are the integers?
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The equation is 

1%2Fx+%2B+1%2F%28x%2B1%29 = 17%2F12.

To solve it, multiply both sides by 12x*(x+1). You ill get

12*(x+1) + 12x = 17x*(x+1).

Simplify and solve this quadratic equation.


Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
as far as i can tell, there is no integer that satisfies this problem.

the consecutive numbers are 1/x and 1/(x+1)

you can graph that function and then graph y = 17/12 and you will find that the intersections of both lines are not integers.

the function you would graph would be y = 1/x + 1/(x+1).

here's the graph.
it shows that the intersection is not an integer.

$$$

to show you that this method works, we'll pick one where the reciprocal of the integers do add up to what the result is.

for example: 1/5 + 1/6 = 6/30 + 5/30 = 11/30

your equation would be y = 1/x + 1/(x+1) again, only this time your intersection would be 11/30 rather than 17/12.

here's the graph.
the graph shows that the intersection is at x = 5.
this agrees with the setup because the first of the integers is x = 5.
therefore the sum of 1/5 + 1/6 = 11/30 as calculated beforehand and as shown on the graph.

$$$

bottom line is that your problem has no solution.
there are no positive integers such that 1/x + 1/(x+1) = 17/12.

in fact, assuming that the smallest integers is 1, there is only one set of integers where the result would be greater than 1.

that would be 1/1 + 1/2 = 3/2 = 1.5.

any other integers would have a result smaller than 1.

1/2 + 1/3 = 5/6

1/3 + 1/4 = 7/12

etc.

you can figure this out for yourself by solving the equation y = 1/x + 1/(x+1)

just pick different values of x and you will see that the result is less than 1 for all values of x > 1.

here's that graph.

$$$

the graph is accurate.

for example, when x = 5, you get 1/5 + 1/6 = 11/30 = .367 as shown on the graph.










Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

The sum of the reciprocals of two consecutive positive integers is 17/12. Write an equation that can be used to find the two integers. What are the integers?
With smaller integer being S, the equation formed is: highlight_green%2817S%5E2+-+7S+-+12+=+0%29
Integers: NO SUCH CONSECUTIVE integers exist!