Question 1035945: Three times Fred’s age plus four times Jane's age equals 71. Fred's age is also three less than two times Jane's age.
How old is Fred?
You can put this solution on YOUR website! Call their ages, f and j. We can then write
3f + 4j = 71
f = 2j - 3
Now substitute the second one into the first one...we get...
3(2j - 3) + 4j = 71
6j - 9 + 4j = 71
10j = 80
j = 8
f = 2(8) - 3 = 13