SOLUTION: keplers third law concerning the motions of the planets in the solar system states that the square of the time for a planet to make a circuit of the sun is proportional to the cube
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Question 1035487: keplers third law concerning the motions of the planets in the solar system states that the square of the time for a planet to make a circuit of the sun is proportional to the cube of the planet's mean distance from the sun. The mean distances from the sun are approximately 93 million miles for the earth and 141 million miles for mars. find the time in years for one circuit of the by mars. Answer by ikleyn(52797) (Show Source):
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keplers third law concerning the motions of the planets in the solar system states that the square of the time for a planet
to make a circuit of the sun is proportional to the cube of the planet's mean distance from the sun.
The mean distances from the sun are approximately 93 million miles for the earth and 141 million miles for mars.
find the time in years for one circuit of the by mars.
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Kepler's third law in this simplified formulation is:
= .
Plug in your data ("1" = Earth, "2" = Mars):
= ---> = = 1.867.
So, the Mars' orbital period around the Sun = 1.867 of the Eart's year.
Wikipedia says Mars' year = 687 Earh's days = = 1.881 of the Earth's year.
