SOLUTION: Identify a possible explicit rule for the nth term of the sequence 1, 1/3, 1/5, 1/7, 1/9, �. A(subscript)n=1/(2n+1) A(subscript)n=1/(2n-1) A(subscript)n=n/(2n-1) A(subscript)n=

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Question 1035433: Identify a possible explicit rule for the nth term of the sequence 1, 1/3, 1/5, 1/7, 1/9, �.
A(subscript)n=1/(2n+1)
A(subscript)n=1/(2n-1)
A(subscript)n=n/(2n-1)
A(subscript)n=n/(2n+1)

I believe you have to take the differences, but it wasnt first differences.
Found 2 solutions by Edwin McCravy, ikleyn:
Answer by Edwin McCravy(20056) (Show Source):
You can put this solution on YOUR website!

I think the best method for you is to write the answers out and see. Plug in n=1 for the first term, n=2 for the second, etc., = 1/3 + 1/5 + 1/7 + ... = 1/1 + 1/3 + 1/5 + ... = 1/1 + 2/3 + 3/5 + ... = 1/3 + 2/5 + 3/7 + ... Now you know which one it is. Edwin

Answer by ikleyn(52787) (Show Source):
You can put this solution on YOUR website!
.
Identify a possible explicit rule for the nth term of the sequence 1, 1/3, 1/5, 1/7, 1/9, �.

1. A(subscript)n=1/(2n+1) 2. A(subscript)n=1/(2n-1) <<<===<<< This one. 3. A(subscript)n=n/(2n-1) 4. A(subscript)n=n/(2n+1)