SOLUTION: The second side of a triangular deck is 5 feet longer than the shorter side and a third side that is 5 feet shorter than twice the length of the shorter side. If the perimeter of t
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Question 1035423: The second side of a triangular deck is 5 feet longer than the shorter side and a third side that is 5 feet shorter than twice the length of the shorter side. If the perimeter of the deck is 48 feet, what are the lenghts of the three sides Answer by macston(5194) (Show Source):
You can put this solution on YOUR website! .
S=shorter (first) side; S+5ft=second side; 2S-5ft=third side
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Perimeter=First side + second side + third side
48 feet=S+(S+5 ft)+(2S-5 ft)
48 feet=4S
12 feet=S
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ANSWER 1: The first side is 12 feet long.
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Second side = S + 5 ft = 12 feet + 5 feet = 17 feet
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ANSWER 2: The second side is 17 feet long.
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Third side=2S-5 feet=2(12 feet)-5 feet=24 feet-5 feet=19 feet
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ANSWER 3: The third side is 19 feet long.
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CHECK:
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Perimeter = first side + second side + third side
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48 feet = 12 feet + 17 feet + 19 feet
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48 feet=48 feet
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