Question 1035361: A shepherd had an unfortunate experience. He was looking after a number (n) of sheep when robbers overpowered him and stole 1/4 of his sheep. He managed to get 3 of the stolen sheep back. The robbers came back and stole 1/3 of the remaining sheep of which he again managed to get 2 back. The third time the robbers overpowered him, they stole 1/2 of the remaining sheep of which he once again managed to get 2 back . He then exactly had n/2 sheep left. Determine the value of n, showing all explanations.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! A shepherd had an unfortunate experience. He was looking after a number (n) of sheep when robbers overpowered him and stole 1/4 of his sheep. He managed to get 3 of the stolen she[ him, they stole 1/2 of the remaining sheep of which he once again managed to get 2 back . He then exactly had n/2 sheep left. Determine the value of n, showing all explanations.
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Start with n sheep
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Then
n - (n/4)+3 = (3/4)n+3
Then
(1/2)[(3/4)n+3]+2 = (3/8)n+(3/2)+2 = (3/8)n + 7/2
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Solve::
Equation (3/8)n+(7/2) = n/2
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3n + 28 = 4n
n = 28 sheep (original number)
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Cheers,
Stan H.
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