SOLUTION: Company is coming for dinner so the house must be spotless. Wade can clean the house in 6 hours while Sarah takes only 4 hours. Wade gets a 2 hour head start before Sarah joins him

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Question 1035330: Company is coming for dinner so the house must be spotless. Wade can clean the house in 6 hours while Sarah takes only 4 hours. Wade gets a 2 hour head start before Sarah joins him in the cleaning. If Wade starts at 11:00 am, what time will they finish cleaning?
Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
Do this solution using time quantities and change to time line later. 
            JOB/HOURS
WADE         1%2F6
SARAH        1%2F4
BOTH         1%2F6%2B1%2F4

The two periods of time are 2 hour and unknown t hours.
Those correspond to just Wade alone, and Wade plus Sarah.

Uniform Work Rates Rule is RT=J to relate rate, time, and amount of job or jobs. The ONE job to be done is "clean the house".

highlight%28%281%2F6%292%2B%281%2F6%2B1%2F4%29t=1%29------------Forming this equation is the most important part of the solution. Solving for t is the easy part. t is not "what time"; but it is "how much time".