SOLUTION: I need help solving this matrice problem dealing with systems. 2x+4y=2 -3x+y=11 This is what I have so far. 2 4 2 -3 1 11 I multiplied the first row by 1/2 to get 1

Algebra ->  Matrices-and-determiminant -> SOLUTION: I need help solving this matrice problem dealing with systems. 2x+4y=2 -3x+y=11 This is what I have so far. 2 4 2 -3 1 11 I multiplied the first row by 1/2 to get 1       Log On


   



Question 1035326: I need help solving this matrice problem dealing with systems.
2x+4y=2
-3x+y=11
This is what I have so far.
2 4 2
-3 1 11
I multiplied the first row by 1/2 to get 1 in place of the 2 in first row.
So then I need to get a 0 at the bottom of the first column. I multiplied -3 by the first row and got -3 -6 and -3. I added the product here to the bottom row. This is where I think I got lost. In the original system there is a 1 on the bottom row second column. When I added the product I got -2, so I'm not sure from here how to finish solving.

Answer by ikleyn(52787) About Me  (Show Source):
You can put this solution on YOUR website!
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I need help solving this matrix problem dealing with systems.
2x+4y=2
-3x+y=11

This is what I have so far.

 2 4 2
-3 1 11

I multiplied the first row by 1/2 to get 1 in place of the 2 in first row.  -Correct.

So then I need to get a 0 at the bottom of the first column.               - Correct

I multiplied -3 by the first row and got -3 -6 and -3.                     - Incorrect.  Multiply by "3" (instead of "-3") 
                                                                             and then add. You will be on the right track. 

I added the product here to the bottom row. This is where I think I got lost. 

In the original system there is a 1 on the bottom row second column. 

When I added the product I got -2, so I'm not sure from here 
how to finish solving?