SOLUTION: (sin3x-sin2x)(sin3x+sin2x)=(2sin{{{x/2}}}cos{{{(5x)/2}}})(2sin{{{(5x)/2}}}cos{{{x/2}}}) Show hiden steps between these two steps.

Algebra ->  Trigonometry-basics -> SOLUTION: (sin3x-sin2x)(sin3x+sin2x)=(2sin{{{x/2}}}cos{{{(5x)/2}}})(2sin{{{(5x)/2}}}cos{{{x/2}}}) Show hiden steps between these two steps.      Log On


   

Question 1035286: (sin3x-sin2x)(sin3x+sin2x)=(2sinx%2F2cos%285x%29%2F2)(2sin%285x%29%2F2cosx%2F2)
Show hiden steps between these two steps.
Answer by ikleyn(52847) About Me  (Show Source):
You can put this solution on YOUR website!
.
The key is this formula of Trigonometry:



(see the lesson Addition and subtraction of trigonometric functions in this site).


Apply it for the first parentheses.

Then apply it again for the second parentheses.