|
Question 1035257: A 3-D painting covers a wall and the adjoining ground. The rectangular painting on the wall is 10 feet tall and 12 feet wide, and it covers the same dimensions on the ground. The wall is perpendicular to the ground. What is the distance between the top left corner of the painting on the wall (A) and the bottom right corner of the painting on the ground (B)? Round your answer to the nearest hundredth of a foot.
Answer by Cromlix(4381)   (Show Source):
You can put this solution on YOUR website! Hi there,
Consider labeling the painting
on the wall ABCD
AB being the top
CD being the bottom
Its corresponding part on
the floor will be labeled
CDEF.
CD being the bottom of
the wall part, but the top
of the floor part.
EF being the bottom of
the floor part.
First we calculate CF which is
the floor diagonal.
CE^2 + EF^2 = CF^2
10^2 + 12^2 = CF^2
CF^2 = 244
CF = √244
CF = 15.62 feet.
Now, we use the triangle
ACF to calculate the distance
from the top left corner to the
bottom right
AC^2 + CF^2 = AF^2
10^2 + 15.62^2 = AF^2
AF = √343.9844
AF = 18.55 feet (2 decimal places)
Hope this helps :-)
|
|
|
| |
