Question 1035188:
The parabola with equation y = 8x – x2 has x-intercepts at 0 and 8. How many units must the parabola be translated down so that the distance between the x-intercepts is 4?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! The parabola with equation y = 8x – x^2 has x-intercepts at 0 and 8. How many units must the parabola be translated down so that the distance between the x-intercepts is 4?
------------------
Original parabola DATA:
Axis of symmetry:: x = 4
Vertex:: (4,f(4)):
f(4) = 8*4-4^2 = 16
Vertex:: (4,16)
----------------------
You want the x-intercepts to be 4-2 = 2 and 4+2 = 6
---------------------
Form::
y = -(x-2)(x-6)
Solve::
y = -(2-2)(2-6)
y = -0(-4) = 0
----
So, the new vertex is (2,0)
------------------------
Ans:: down from (2,16) to (2,0)
down 16 units
------------------
Cheers,
Stan H.
-------------
|
|
|
