Question 1035187: An urn contains 3 white, 4 blue and 5 red balls. What is the probability of drawing, without replacement, first a white, then a blue, and finally a red ball? Express your answer as a common fraction.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! An urn contains 3 white, 4 blue and 5 red balls. What is the probability of drawing, without replacement, first a white, then a blue, and finally a red ball? Express your answer as a common fraction.
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Ans: (1/3)(1/4)(1/5) = 1/60
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Cheers,
Stan H.
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