SOLUTION: solve 8m^2+20m=12 for m by factoring.

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Question 1035161: solve 8m^2+20m=12 for m by factoring.
Found 3 solutions by josgarithmetic, Alan3354, ikleyn:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
2m%5E2%2B5m=3

2m%5E2%2B5m-3=0

Look for the binomial factor combination which works.
(2m  1)(m  3)--------------- 1 and 6


(2m  3)(m  1)---------------3 and 2

The first one.
highlight%28%282m-1%29%28m%2B3%29%29---------this will do it.

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
solve 8m^2+20m=12 for m by factoring.
----
8m^2+20m=12
8m^2+20m-12 = 0
2m^2 + 5m - 3 = 0
(2m - 1)*(m + 3) = 0
m = 1/2
m = -3

Answer by ikleyn(52787) About Me  (Show Source):
You can put this solution on YOUR website!
.
solve 8m^2+20m=12 for m by factoring.
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8m%5E2+%2B+20m = 12,

8m%5E2+%2B+20m+-+12 = 0,

2m%5E2+%2B+5m+-+3 = 0,

(2m-1)*(m+3) = 0.

m = 1%2F2   and/or  m = -3.